5^2-10x+25=40

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Solution for 5^2-10x+25=40 equation: 



5^2-10x+25=40

We move all terms to the left:

5^2-10x+25-(40)=0

determiningTheFunctionDomain
-10x+25-40+5^2=0

We add all the numbers together, and all the variables

-10x+10=0

We move all terms containing x to the left, all other terms to the right

-10x=-10

x=-10/-10

x=1

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